Aparticular fluid has a shear stress of 0.005 n m-at a shear rate of 1 s- and a shear stress of 2 n m-2 at a shear rate of 50 - present an argument as to whether this fluid is newtonian or non-newtonian.

The given fluid is Non-Newtonian

Explanation:

Given:

τ₁ = 0.005 N/m²

 = 1 s⁻¹

τ₂ = 2 N/m²

 = 50 s⁻¹

Now,

From Newton's law of viscosity

τ =

Here, μ is the dynamic viscosity of the fluid

thus,

for the first case

0.005 = μ₁ × 1

or

μ₁ = 0.005 Pa.s

similarly

For the second case

2 = μ₂ × 50

or

μ₂ = 0.04 Pa.s

Since,

μ₁ ≠ μ₂

The given fluid is Non-Newtonian

as for the Newtonian Fluid the value of dynamic viscosity remains constant

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